Question

Find the route of the equation x2 + x - p(px-1)=0 , where p is a constant

Answer 1

Given: equation x

2

+x−p(p+1)=0, where p is a constant

To find the roots of the equation

Sol: the given equation is of form ax

2

+bx+c=0∴a=1,b=1,c=−p(p+1)

We know the roots of the equation can be find out using the formula,

x=

2a

−b±

b

2

−4ac

Substituting the values of a, b, c, we get

x=

2

−1±

1

2

−4(1)(−p(p+1)

x=

2

−1±

1+4p

2

+4p

x=

2

−1±(2p+1)

or x=

2

−1+(2p+1)

,x=

2

−1−(2p+1)

⇒x=p,x=−(p+1) are the roots of the given equation

HOPE IT HELP U //