Find
the
Rs 36000 at 10% p.a. for 3 years
compound interest on
Compounded annually
Answers
Answered by
0
Answer: the answer is given below
Step-by-step explanation:
For the first year
P=Rs36,000
N=1year
R=10 %
We have S.I.=
100
PNR
=
100
36,000×1×10
=Rs3,600
And Amount at the end of first year P+S.I.=Rs36,000+Rs3,600=Rs39,600
Now, for the second year
P=Rs39,600
N=1year
R=12 %
We have S.I.=
100
PNR
=
100
39,600×1×12
=Rs4,752
And Amount at the end of second year P+S.I.=Rs39,600+Rs4,752=Rs44,352
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