Find the rth term of an A.P sum of those forst n terms is 2n + 3n(sqaure)
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Answered by
6
Hi
Here is your answer,
Tn = Sn = Sn-₁
= (2n + 3n²) - [2(n - 1) + 3(n - 1)²]
= ( 2n + 3n²) - [ 2n - 2 + 3(n² + 1 - 2n)]
= 2n + 3n² - 2n + 2 - 3n² - 3 + 6n
= 6n - 1
∴ rth term (Tr) = 6r - 1
Hope it helps you !
Here is your answer,
Tn = Sn = Sn-₁
= (2n + 3n²) - [2(n - 1) + 3(n - 1)²]
= ( 2n + 3n²) - [ 2n - 2 + 3(n² + 1 - 2n)]
= 2n + 3n² - 2n + 2 - 3n² - 3 + 6n
= 6n - 1
∴ rth term (Tr) = 6r - 1
Hope it helps you !
Answered by
0
hello...
Tn = Sn = Sn-1
(2n + 3n²) - [2(n - 1) + 3(n - 1)²]
( 2n + 3n²) - [ 2n - 2 + 3(n² + 1 - 2n)]
2n + 3n² - 2n + 2 - 3n² - 3 + 6n
6n - 1
rth term = 6r - 1
Tn = Sn = Sn-1
(2n + 3n²) - [2(n - 1) + 3(n - 1)²]
( 2n + 3n²) - [ 2n - 2 + 3(n² + 1 - 2n)]
2n + 3n² - 2n + 2 - 3n² - 3 + 6n
6n - 1
rth term = 6r - 1
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