Question

Find the S.I. on 3000 at 64

1% per annum for the period from 4th February 2020 to 18th

April 2020​

Answer 1

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GIVEN :-

P = ₹3000

R = 6¼%.

SOLUTION :-

Time = (24+31+18)days

= 73 days = 73/365 years = 1/5 years. 

P = Rs.3000

R = 6 ¼ %

p.a = 25/4%

S.I = Rs.(3,000*(25/4)*(1/5)*(1/100))

= Rs.37.50.

Answer 2

Step-by-step explanation:

The period from 4th February, 2019 to 3rd April, 2019 covers exactly 2 months. Thereafter, 4th April, 2019 to 18th April, 2019 spans 15 days, i. e., 0.5 month (considering April to May transition of 30 days).

So, simple interest of 2.5 months needs to be calculated.

It shall be (3000)*(25 / 4)*(1 / 100)* (2.5 / 12) rupees

= 39.0625 rupees

= 39 rupees 06 paisa.

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