find the s of vectors i-j+2k and 2i+3j-4k
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Answer:
Correct option is
A
cos−1283
Let a
=3i+j+2k and b
=2i−2j+4k.
Now angle between a
and b
be
cos−1(∣a
∣∣b
∣a
.b
)=cos−1(14
.24
6−2+8)=cos−1(283
).
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