Physics, asked by shrishti0864, 3 months ago

Find the safe limit of current for a bulb rated 50 W, 220 V​

Answers

Answered by sonika2369
1

Answer:

The formula is: Current = watts / volts Therefore, if the light bulb is connected to a ... So current, I =W /V, so it will be 60 watts /220v =0.27 amperes approximately

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Answered by Anonymous
4

Answer:

P=50W

V=220V

t=20minutes

t=?

∴E=P×t

P=50W=

1000

50

kW=0.05kW

t=20minutes=

60

20

h=

3

1

h

∴E=P×t=0.05×

3

1

=0.016kWh.

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