Question

find the SD of first 41 natural number.​

Answer 1

Answer:

do you know what is xd

Step-by-step explanation:

please say me........

Answer 2

Step-by-step explanation:

Mean, u=

n

(1+2+3...+n)

∴u=

2

1

(n+1)

Variance, σ

2

=

n

∑(x

i

−u)

2

=

n

∑x

i

2

−u

2

∴σ

2

=

n

∑n

2

−

2

1

(n+1)

2

∴σ

2

=

n

1

n

n(n+1)(2n+1)

−(

2

1

(n+1))

2

∴σ

2

=

12

n

2

−1

Standard Deviation, S.D=

σ

2

∴S.D=\sqrt{\dfrac{n^2-1}{12}}