Find the second and term and nth term of an A.P Whose 6th term is 12 and 8th term is 22
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nth term of an AP whose 1st term is "a" and common difference is "d"
is an= a+(n-1)d
According to question
6th term= 12 8th term=22
a+5d=12-----Equation 1
a+7d=22------Equation 2
Equation 2 - Equation 1
= 2d=10
d=5
Substituting d=5 in equation 1
a+5*5=12
a= 12-25
a= -13
2nd term is
a+(2-1)d
= a+d = -13+5 = -8
2nd term = -8
nth term
= a+(n-1)d
= -13+(n-1)5
= -13-5+5n
= -18+5n
nth term = -18+5n
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you..........................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
nth term of an AP whose 1st term is "a" and common difference is "d"
is an= a+(n-1)d
According to question
6th term= 12 8th term=22
a+5d=12-----Equation 1
a+7d=22------Equation 2
Equation 2 - Equation 1
= 2d=10
d=5
Substituting d=5 in equation 1
a+5*5=12
a= 12-25
a= -13
2nd term is
a+(2-1)d
= a+d = -13+5 = -8
2nd term = -8
nth term
= a+(n-1)d
= -13+(n-1)5
= -13-5+5n
= -18+5n
nth term = -18+5n
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you..........................
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