Question

Find the second derivative of y(x) = 2x^5 + 4x⁴ - x³ + 2x + 1​

Answer 1

Step-by-step explanation:

y(x) = 2x^5 + 4x⁴ - x³ + 2x + 1, first derivative would be;

y'(x) = 10x⁴ + 16x³ - 3x² + 2

For second derivative:

y''(x) = 40x³ + 48x² - 6x

Recall that derivative of x = 1, any constant would always be equal to 0.

Answer 2

Answer:

Math is awesome for guy up above.