Find the second least number which when
divided by 8,9,,10 leaves remainder 7 is
each cases
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Answered by
14
Answer:
- Find the least number which when divided by 6,7, 8, 9,12 leaves the same remainder 2 in each case. Required number=(LCM of 6,7,8,9,12)+2=504+2=506.
Answered by
12
Find the second least number which whendivided by 8,9,,10 leaves remainder 7 iseach cases.
Whenever you get questions like this find out the LCM of all the numbers. The LCM will be divisible by all the numbers. Add 1 to the LCM and that is the answer.
Here find out the LCM of 6,7,8,9 and 12.
The LCM is 504 and the answer is 504 + 1 = 505
There will be multiple answers like 1009, 1513, and so on but the least is 505
Hope It Helps uhh~
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