Find the second order Partial derivative of tan [tan^-1x
+ tan^-1y]
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Answer:
(x+y) ÷ (1-xy)
Step-by-step explaination:
tan[tan^-1x + tan^-1y]
=tan[{tan^-1(x+y)÷(1-xy)}]
=(x+y) ÷ (1-xy)
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