Find the second term and nth term of an A.P. whose 6th term is 12 and 8th term is 22.
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Given :
Sixth term of an A.P = 12
a + 5d = 12 ------(1)
Eighth term of an A.P = 22
a + 7d = 22 ----(2)
Solve eq - (1) & (2) to find difference (d)
a + 5d = 12
a + 7d = 22
(-)
-----------------
-2d = -10
d = 10/2
d = 5
Difference = 5
Substitute d in eq - (1) to find first term (a)
a + 5d = 12
a + 5(5) = 12
a + 25 = 12
a = 12 - 25
a = -13
First term = -13
Second term :
= a + d
= -13 + 5
= -8
an = a + ( n - 1 )d
= -13 + ( n - 1) 5
= -13 + 5n - 5
= -18 + 5n
= 5n - 18
Therefore, nth term of A.P is 5n - 18 and second term of A.P is -8.
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