Find the second term and nth term of an A.P. whose 6th term is 12and 8th term is 22
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Step-by-step explanation:
Let a and d be the first term and the common difference of the given AP respectively. Then,
a
6
=12⇒a+5d=12 ...(1)
a
8
=22⇒a+7d=22 ...(2)
On subtracting (2) from (1), we get
2d=10⇒d=5
Putting d=5 in (1), we get
a=12−5×5=−13
Now, a
2
=a+d=−13+5=−8 and
a
n
=a+(n−1)d
=−13+(n−1)×5
=5n−18
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