Math, asked by devanshi4a12uep, 10 days ago

Find the secret number which is larger than half of 120 .It is also more than 7tens and less than 8 tens . The tens digit is one more than the ones digit and together the digits have a sum of 13

Answers

Answered by pratiksharprajapati
0

Answer:

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Answered by Swarup1998
2

Let the number be x.

Step 1.

The secret number is larger than half of 120.

Here half of 120 is (120 ÷ 2) = 60

Then, x > 60

Step 2.

It is also more than 7 tens and less than 8 tens.

Here 7 tens = 70 & 8 tens = 80

Then, 70 < x < 80

Step 3.

The tens digit is one more than the ones digit.

The numbers between 70 and 80 are 71, 72, 73, 74, 75, 76, 77, 78 and 79.

Of these, the only number whose tens digit is one more than the one digit, is 76.

Then x = 76.

Step 4.

Together the digits have a sum of 13.

Here x = 76 and 7 + 6 = 13.

Final answer: The secret number is 13.

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