Question

Find the selling price (SP) if a profit of 5% is made in :

(a) a cycle of ₹620 with ₹40 as overhead

(b) a lawn mower bought at ₹1265 with ₹34
as transportation charges.


:)​

Answer 1

Answer 1 :

★ Given :

• Selling Price of cycle = ₹620
• Overhead charges = ₹40
• Profit% = 5%

★ To Find :

• Selling Price

★ Solution :

~Total cost price :

$\longrightarrow$ Total Cost Price = Cost Price + Overhead charges

$\longrightarrow$ Total Cost Price = ₹620 + ₹40

$\longrightarrow$ Total Cost Price = ₹660

So, total cost price = ₹660.

~Now, finding selling price :

★ We know that,

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = C. P. + C. P. \times P\%$

Putting the vales,

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 660 + 660 \times 5\%$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 660 + 66 \cancel0 \times \frac{5}{10 \cancel0}$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 660 + 66 \times \frac{ \not5}{ \cancel{10}}$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 660 + \cancel{ 66 }\times \frac{ 1}{{ \not2}}$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 660 + 33$

$\red{ \sf \displaystyle \longrightarrow \boxed{\bf \: Selling \: Price = Rs. \: 693} \: \bigstar}$

Hence, the selling price is Rs. 693.

Answer 2 :

★ Given :

• Selling Price = ₹1264
• Transportation charges = ₹34
• Profit% = 5%

★ To Find :

• Selling Price

★ Solution :

~Total cost price :

$\longrightarrow$ Total Cost Price = Cost Price + Transportation charges

$\longrightarrow$ Total Cost Price = ₹1264 + ₹34

$\longrightarrow$ Total Cost Price = ₹1,298

So, total cost price = ₹1,298.

So, total cost price = ₹1,298. ~Now, finding selling price :

★ We know that,

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = C. P. + C. P. \times P\%$

Putting the values,

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 1298 + 1298 \times 5\%$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 1298 + 1298 \times \frac{ \cancel5}{ \cancel{100}}$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 1298 + 1298 \times \frac{ 1}{20}$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 1298 + \cancel{1298} \times \frac{ 1}{ \cancel{20} }$

$\sf \displaystyle \longrightarrow \sf \: Selling \: Price = 1298 +64.9$

$\pink{ \sf \displaystyle \longrightarrow \boxed{\bf \: Selling \: Price = Rs. \: 1,362.9} \: \bigstar}$

Hence, the selling price is ₹1,362.9!

Answer 2

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Question \; :- }}}}}}}$

Find the selling price (SP) if a profit of 5% is made in :

(a) a cycle of ₹620 with ₹40 as overhead

(b) a lawn mower bought at ₹1265 with ₹34

as transportation charges.

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Given \; :- }}}}}}}$

PROFIT = 5%

(a) TOTAL COST PRICE = ₹ (620 + 40) = ₹ 660

(b) TOTAL COST PRICE = ₹ (1265 + 34) = ₹ 1299

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}$

• SELLING PRICE

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Formula \: Used \; :- }}}}}}}$

• SELLING PRICE = COST PRICE + PROFIT

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Solution \; :- }}}}}}}$

(a) a cycle of ₹620 with ₹40 as overhead :-

• PROFIT = 5% of ₹ 660

• => 33

• SELLING PRICE :-

• => ₹ (660 + 33)

• => ₹ 693

(b) a lawn mower bought at ₹1265 with ₹34

as transportation charges.

• PROFIT = 5% of ₹1299

• => 64•95

• SELLING PRICE :-

• => ₹ (1299 + 64•95)

• => ₹ 1363•95

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Answer \; :- }}}}}}}$

(a) a cycle of ₹620 with ₹40 as overhead.

• => ₹ 693

(b) a lawn mower bought at ₹1265 with ₹34

as transportation charges.

• => ₹ 1363•95