Question

Find the semi-perimeter of a triangle whose sides are 26 cm, 28 cm, 30 cm ?

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Answer 1

Given : The three sides of Triangle is 26 cm, 28 cm and 30 cm.

To Find : Semi-Perimeter of Triangle ?

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❍ Let's consider A, B & C be the three sides of Triangle.

Finding Semi-Perimeter of Triangle is given by :

• $\boxed{\sf\pink{Semi-Perimeter_{(Triangle)}~=\dfrac{A ~+~B~+~ C}{2}}}$

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Solution : Here A is the First Side of Triangle, B is the Second side of Triangle and C is the Third side of Triangle. and given that all three sides of Triangle are 26 cm, 28 cm and 30 cm.

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$\underline{\bf{Now~ By ~Substituting~ the ~Given ~Values~:}}$

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$~\longmapsto{\sf{Semi-Perimeter~=~\dfrac{26~+~28~+~30}{2}}}$

$~\longmapsto{\sf{Semi-Perimeter~=~\dfrac{26~+58}{2}}}$

$~\longmapsto{\sf{Semi-Perimeter~=~\cancel\dfrac{84}{2}}}$

$~\longmapsto{\underline{\boxed{\frak{\pink{Semi-Perimeter~=~42~cm}}}}}$★

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Hence,

$\therefore\underline{\sf{Semi-Perimeter ~of ~Triangle~ is~\bf{42~cm}}}$

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More Information :

• ${\sf{Perimeter_{(Triangle)}~=~Side~A~+~Side~B~+~Side~C}}$

• ${\sf{Perimeter_{(Triangle)}~=~2(Length~+~Breadth}}$

• ${\sf{Perimeter_{(Triangle)}~=~4~×~Side}}$

• ${\sf{Circumference_{(Circle)}~=~2~×~π~×~Radius}}$