Question

find the semi perimeter of a triangle with sides 8cm,12cm and 30cm

Answer 1

$\LARGE\star\mathfrak{\underline{\underline{\red{answer: }}}}$

$\underline{\sf{given : }} \\ \sf{first \: side \: (a) =8cm } \\ \sf{second \: side \: (b) = 12cm} \\ \sf{third \: side \: (c) = 30cm}$

$\sf{we \: know \: that : } \\ \sf{semiperimeter \: of \: a \: triangle \: (s) = \frac{a + b + c}{2} }$

$\underline{ \sf{solution : }} \\ \\ \sf{s = \frac{a + b + c}{2} } \\ \\ \sf{s = \frac{8 + 12 + 30}{2} } \\ \\ \sf{s = \frac{50}{2} } \\ \\ \sf{s = \frac{ \cancel{50}}{ \cancel{2}} } \\ \\ \sf{s = 25cm}$

$\boxed{ \sf{semiperimeter \: of \: triangle \: = 25 \: cm}}$

Answer 2

$\rm \rightarrowtail \: Perimeter_{(Triangle)}=a+b+c$

$\rm \rightarrowtail \: Perimeter_{(Triangle)} = 8 + 12 + 30 = 50cm$

$\rm \rightarrowtail \: Semi - Perimeter_{(Triangle)} = \dfrac{1}{2}×Perimeter$

$\rm \rightarrowtail \: Semi - Perimeter_{(Triangle)} = \dfrac{1}{2}×50$

${ \boxed{ \frak {\pink{\: Semi - Perimeter_{(Triangle)} = 25cm}}}}$