find the sentroid of the triangle whos vertices are (2'-3) '(-4'2) nad (8'13)
Answers
Answered by
2
Answer:
(2,4)
Step-by-step explanation:
let (X1,y1) = (2,-3)
(X2,y2) = (-4,2)
(x3,y3) = (8,13)
by the centroid formula,
centroid (x,y) = [(X1+X2+x3)/3, (y1+y2+y3)/3]
(x,y) = [(2-4+8)/3, (-3+2+13)/3]
(x,y) = [6/3,12/3]
(x,y)= (2,4)
Answered by
0
Centroid of triangle = (2,4)
Attachments:
Similar questions