Question

Find the separate equations of
3x²+2xy-y²=0​

Answer 1

Answer:

Factorising 3x2 + 2xy – y2

Factorising 3x2 + 2xy – y2 we ge

Factorising 3x2 + 2xy – y2 we get 3x2 + 3xy – xy – y2 = 3x

Factorising 3x2 + 2xy – y2 we get 3x2 + 3xy – xy – y2 = 3x (x + y) – y (x + y) = (3 x – y)(x + y)

Factorising 3x2 + 2xy – y2 we get 3x2 + 3xy – xy – y2 = 3x (x + y) – y (x + y) = (3 x – y)(x + y) So

Factorising 3x2 + 2xy – y2 we get 3x2 + 3xy – xy – y2 = 3x (x + y) – y (x + y) = (3 x – y)(x + y) So 3x2 + 2xy – y2 = 0

Factorising 3x2 + 2xy – y2 we get 3x2 + 3xy – xy – y2 = 3x (x + y) – y (x + y) = (3 x – y)(x + y) So 3x2 + 2xy – y2 = 0 ⇒ (3x – y) (x + y) = 0

⇒ 3x – y = 0 and x + y

Step-by-step explanation:

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