Question

find the seres of 10³+11³+12³.......+20³​

Answer 1

SOLUTION:

• ${10}^{3} + {11}^{3} + {12}^{3} + ... {20}^{3} \\ = {1}^{3 } + {2}^{3} + {3}^{3} + ... + {20}^{3} - {1}^{3} - {2}^{3} - {3}^{3} - ... - {9}^{3} \\= {( \frac{ {20}^{2} + 20 }{2} )}^{2} - {( \frac{ {9}^{2} + 9 }{2} )}^{2} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\44055$

///MARK IT BRAINLIEST///

Answer 2

Step-by-step explanation:

10³645³946³

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