Question

Find the series 42:72::?:156

Answer 1

The series is in the form of $\dfrac{a}{b} = \dfrac{c}{d}$

So, let a be 42, b be 72, c be x and d be 156


According to the question

$\dfrac{a}{b} = \dfrac{c}{d}$

☛ $\dfrac{42}{72} = \dfrac{x}{156}$

Reduce the first fraction by 6

☛ $\dfrac{42 \div 6}{72 \div 6} = \dfrac{x}{156}$

☛ $\dfrac{7}{12} = \dfrac{x}{156}$

Cross multiply

☛ $7 \times 156\:=\:12 \times x$

☛ $1092\:=\:12x$

☛ $x\:=\:\dfrac{1092}{12}$

☛ $x\:=\:91$


∴ The value of x or c is $\boxed{\boxed{\text{91}}}$

Answer 2

$\huge{\mathfrak{\underline{\underline {Question:}}}}$



Find the series 42 : 72 :: ? : 156



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$\huge{\mathfrak{\underline{\underline {Answer:}}}}$



▶ 42 : 72 :: 91 : 156



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$\huge{\mathfrak{\underline{\underline {Brainly \: Solution:}}}}$



▶ Let the unknown number be x.



➡ The numbers 42, 72, x and 156 are in proportion.



$\therefore \sf42 \ratio 72 \ratio \ratio x \ratio 156 \\ \\ \to \sf72 \times x = 42 \times 156 \\ \\ \sf \to x = \frac{42 \times 156}{72} \\ \\ \sf \to x = \frac{ \cancel{6552} \: \: ^{ \large{91}} }{ \cancel{72}}$
$\huge \orange{ \boxed{ \boxed{ \sf{ \therefore x = 91 }}}}$



✔✔ Hence, it is solved ✅✅.



$\huge \green{ \boxed{ \boxed{ \mathscr{THANKS}}}}$

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