Find the series in
Python
0 7 26 63......n terms
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Answer:
X^3 - 1 (where x is any number..1,2,3,…………n)
The series will be
1^3-1=0
2^3-1=7
3^3-1=26
4^3-1=63
5^3-1=124
6^3-1=215
0, 7, 26, 63,124,215.........
hopefully this helps you :)
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