Find the set of zeros of cos(3x + 2)
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Answer:
(3x+2)=0
3x+2=0
3x=-2
x=-2/3
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Answer:
- cos(3x-2) = 1
- cos(3x-2) = 1cos(3x-2)= cos0
- cos(3x-2) = 1cos(3x-2)= cos03x- 2 =2npi
- cos(3x-2) = 1cos(3x-2)= cos03x- 2 =2npi x= 2npi + 2/3
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