Question

find the seventh term from the end of the series: √2 , 2 , 2√2 , ............, 32


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Answer 1

32,..........................2√2,2,√2

a= 32 , r= 1/√2

Tn = ar^n-1

T7 = 32 (1/√2)^7-1

T7= 32(1/√2)^6

T7= 32×1/8

T7= 4

Answer 2

Answer:

4

Step-by-step explanation:

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