find the seventh term of an ap whose second term is 13 and fifth term is 25
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Step-by-step explanation:
using tu formula the seventh term is 33
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Step-by-step explanation:
Here a2=13
therefore a+(n-1)*d
here let first term be a and common difference be d
.
. . a+(2-1)*d=13
or a+d=13 equation 1
and the fifth term is 25
.
. . a+(5-1)*d=25
or a+4d=25 equation 2
now eq..2-1 we get d=4
now putting the value of d in eq..1 we get
a+4=13
a=9
now the 7th term
a7 = a+(n-1)d
9+(7-1)*4=33
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