find the shaded region....
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First by Pythagoras theorem find the missing side of the triangle.
AB* + BC* = AC* (*means square)
AC = 35
area of triangle + area of semi circle (AC) - the area of the quadrant
1/2 X 21 X 28 + π X 17.5 X 17.5 - 1/4 X π X 21 X 21
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Area of triangle=>1/2 * 21 * 28=294cm².
AC=√(28+21)²
AC=√49²
AC=49cm
So, area of semicircle around it's hypotenuse:-
1/2πr²=>1/2π(49/2)²=1/2*22/7*49*49/4
=943.25cm²
And, area of small semicircle=
1/2πr²=1/2*22/7*21*21=693
therefore,area of shaded region=294+943.25-693=544.25cm²
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