find the shaded region. I follow u .please answer
Answers
Answer:
here, You haven't mention what we have to find of the shaded region Area Or Perimeter.
Figure (i) area = 68cm² and
Figure (ii) area = 85cm²
Step-by-step explanation:
here, In figure (i) area of rectangle ABCD = L x B
= 13 x 7 = 91cm²
now, area of Δ AEH = 1/2 x 7 x 4
= 14cm²
and, area of Δ BFH = 1/2 x 6 x 3
= 9cm²
Area of shaded region = area of rectangle ABCD - (area of Δ AEH + area of Δ BFH)
= 91cm² - (14cm² + 9cm²)
= 91cm² - 23cm²
= 68cm²
∴ Area of shaded region of figure (i) = 68cm²
now, Area of rectangle LMNP = L x B
= 14cm x 15cm = 210cm²
Area of Δ LMY = 1/2 x 14 x 5
= 35cm²
Area of Δ XPY = 1/2 x 10 x 6
= 30cm²
and, Area of Δ XNM = 1/2 x 8 x 15
= 60cm²
now, Area of shaded region = area of rectangle LMNP - (area of Δ LMY + area of Δ XPY + area of Δ XNM)
= 210cm² - (35cm² + 30cm² + 60cm²)
= 210cm² - 125cm²
= 85cm²
∴ Area of shaded region of figure (ii) = 85cm².
hope it will help you.
Answer:
in rectangle ABCD,
AB=CD=AH+HB=7+6=13cm
AD=BC=4+3=7cm
area of rectangle =l×b=13×7=91cm²
area of triangle HAE=1/2 ×AH ×AE=1/2×7×4=14cm²
area of triangle HBF=1/2×HB×BF=1/2×6×3=9cm²
shaded region =area of rectangle-(area of HAE +area of
HBF)
=91-(14+9)=91-23=68cm²
in rectangle LMNP,
PN=LM=6+8=14cm
MN=LP=15cm
area of rectangle =14×15=210cm²
area of triangle YPX=1/2× YP×PX=1/2 ×10×6=30cm²
area of triangle MNX=1/2×MN×XN=1/2×15×8=15×4=60cm²
area of triangle YLM=1/2 ×LM×YL=1/2 ×14×5=7×5=35cm²
area of shaded region =area of rectangle-(area of YPX+area of MNX+area of YLM)
=210-(30+60+35)=210-125=85cm²
hope it helps you and don't forget to follow me