Question

find the shortest and longest wavelength of balmer series for H-atom​

Answer 1

Answer:

the shortest wavelength is 1215.4Ao. So this is the required shortest and the longest wavelength of the Balmer series of hydrogen (H2) spectrum.

Answer 2

Answer:

Answer:⇒λ=431.097×107=(43)0.91157×10−7=1.2154×10−7 meter. ⇒λ=1215.4×10−10 meter. So the shortest wavelength is 1215.4Ao. So this is the required shortest and the longest wavelength of the Balmer series of hydrogen (H2) spectrum.