Physics, asked by sherikhan444555, 9 months ago

Find the shortest wavelength present in the radiation from an x-ray machine whose accelerating potential is 50,000 V.​

Answers

Answered by tejasya2007
4

Answer:

Explanation:

We can determine the minimum wavelength of emitted x-rays, using the following formula:

λmin=hc/eVλmin=hc/eV

Where h is Planck’s constant, c is speed of light and eV the applied potential (for this purpose, the same as KV).

So, in your case it would be:

λmin=1.23984193/50=0.0247968386pm

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