Find the shortest wavelength present in the radiation from an x-ray machine whose accelerating potential is 50,000 V.
Answers
Answered by
4
Answer:
Explanation:
We can determine the minimum wavelength of emitted x-rays, using the following formula:
λmin=hc/eVλmin=hc/eV
Where h is Planck’s constant, c is speed of light and eV the applied potential (for this purpose, the same as KV).
So, in your case it would be:
λmin=1.23984193/50=0.0247968386pm
Similar questions