Question

Find the SI of Rs. 1800 at $\sf3\dfrac{1}{2}$per annum for $\sf2\dfrac{1}{2}$.

Answer 1

Given:

• Principal =1800 rupees
• Rate = $\sf3\dfrac{1}{2}$%
• Time = $\sf2\dfrac{1}{2}$years

To Find:

• Simple Interest =?

Solution:

Given,

• P = 1800
• R =$\sf3\dfrac{1}{2}$%
• T=$\sf2\dfrac{1}{2}$ years

As we know that

${\qquad}{\sf{\underline{\boxed{\red{ \sf{simple \: interest = \frac{prt}{100}}}}}}}$

Now put the values

$\: \sf \implies \: simple \: interest = \frac{1800 \times 7 \times 5}{100 \times 2 \times 2} \\ \\ \: \sf \implies \: simple \: interest = \frac{315}{2} = 157.50 \: rupees$

${\therefore}{\small{\sf{\underline{hence \: simple \: interest \: is \: 157.50 \: rupees}}}}$