Find the si on rupees 15000 on 10% pa of 2.5 years
plz solve and tell don't do direct answer plzzzz
Answers
Answered by
0
Answer:
Step-by-step explanation:
(i)
A=P(1+
100
r
)
n
=15000(1+
100
10
)
2
=Rs18150
CI=A−P=Rs3150
(ii)
A=P(1+
100
r/m
)
n∗m
=156250(1+
100
8/2
)
1.5∗2
=Rs175760
CI=A−P=Rs19510
(iii)
A=P(1+
100
r/m
)
n∗m
=100000(1+
100
4/4
)
0.75∗4
=Rs103030.1≈Rs103030
CI=A−P=Rs3030
Answered by
0
Answer:
Rs.3750
Step-by-step explanation:
Principal (P) = Rs.15000
Rate (R) = 10%
Time (T) = 2.5 years
Simple Interest (SI) = PRT/100
=> SI = 15000 × 10 × 2.5/100
=> SI = Rs.3750
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