Question

find the side and perimeter of a square whose diagonal is 10 cm​

Answer 1

Given:

AB=BC=CD=DA

Explanation:

According to the Pythagoras theorem , in triangle ABD

AB^2 + AD^2 = BD^2

a^2 + a^2 = 10^2

2a^2=100

a^2=50

a=root 50

a=5 root 2 cm

Hence, the side of square is 5 root 2 cm

Now,

perimeter of square = 4 × ( side )

= 4 × a

= 4 × 5 root 2 cm

=20 root 2 cm

Hence, the perimeters of square 20 root 2 cm.

Answer 2

Step-by-step explanation:

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