Question

find the side and perimeter of a square whose diagonal is 10 cm

Answer 1

Let ABCD be a square whose diagonal AC = 10cm now in triangle ACB using pgt ab2 +cb2=ac2 so ab2+ab2=100 2ab2=100  ab 2=50 ab =5root 2 so side =5root2 cm and perimeter 20root2 cmsquare

Step-by-step explanation:

Answer 2

Step-by-step explanation:

In a square of side say a cm, any diagonal divide the square into two right triangles of equal dimensions.

Thus a² + a² = 102

⇒ 2a² = 100

⇒ a² = 50

a = 5√2 cm

perimeter = 4a

= 4×5√2

= 20√2

Perimeter of square = 20√2cm