Find the side lengths of a triangle with a perimeter of 120 in. and the ratio of the
sides as 3:4:5.
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Let the sides of triangle ABC be 3x , 4x and 5x
And it's perimeter is 120
perimeter of triangle = Sum of all sides
120 = 3x + 4x + 5x
120 = 12x
120÷12 = x
10 = x
1st side = 3x = 3×10
= 30
2nd side = 4x = 4×10 = 40
3rd side = 5×10 = 50
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