Question

Find the side of a rare whose
area is (4222
(4 x + 3)
(4x+12
(2x + 3)
None of these​

Answer 1

Answer:

y=x^2 - 4x - 12

(a) The x-intercepts:

evaluating at y=0

=> 0=x^2 - 4x - 12

=> 0=x^2 -6x+2x -12

=> (x-6) (x+2)

x=6 and -2

(b) The y-intercept

evaluating at x=0

=> y= 0^2 - 4(0) -12

y= -12

(c) Coordinates of the vertex

h= - b/2a, where b= -4, a= 1

so h= -(-4)/2(1) = 4/2 = 2

and now evaluating the equation at h=2,we get k

=> k= (2)^2 -4(2) -12

=> k= 4-8-12

k=-16

vertex (h,k) = (2,-16)

Answer 2

Answer:

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