Question

find the side of a rhombus whose diagonal are 10 cm and 24 cm​

Answer 1

Answer:

13 cm

Step-by-step explanation:

We know that in a rhombus, the diagonals bisected each other at 90°.

In the figure, AC = 24 cm

BD = 10 cm

Also, DO = BO = 5 cm

CO = AO = 12 cm

In ∆ AOB,

By Pythagoras Theorem,

(AB)² = (AO)² + (BO)²

Putting known values, we get

(AB)² = (5)² + (12)²

AB² = 25 + 144

AB² = 169

AB = √169

AB = 13 cm

Hence, the side of rhombus is 13 cm.