Question

find the side of a square whose area is equal to the area of rectangle with sides 6.4 cm and 2.5 CM

Answer 1

area of rectangle =l×b
=6.4×2.5
=16 cm^2
area of rectangle =area of square
area of square=16 cm^2
area of square =s^2
s^2=16^2
s=4 cm

Answer 2

Given:-

• The area of rectangle = area of square
• Length of rectangle is 6.4 and breadth is 2.5 cm.

To Find:-

• Side of square?

Solution:-

Area of rectangle

$\star{ \underline{ \boxed{ \rm{ \pink{length \times breadth}}}}}$

Finding the area

$\Longrightarrow6.4 \times 2.5 \\ \\ \Longrightarrow \rm16 \: cm$

Area of square

$\star{ \underline{ \boxed{ \rm{ \green{ {side}^{2} }}}}}$

Finding the side

$\Longrightarrow {x}^{2} = 16 \: cm \\ \\ \Longrightarrow x = \sqrt{16} \\ \\ \Longrightarrow x = 4 \: cm$

Hence, the measure of side of square is 4 cm.