Question

find the side of an equilateral triangle which has the same area as that of a triangle of sides 6cm ,8cm and 10 cm.also find the length of an alitude of an equateral triangle.​

Answer 1

Answer:The sides are 6cm,8cm,10cm

s=  

2

6+8+10

​  

=  

2

24

​  

=12

The area is given as  

s(s−a)(s−b)(s−c)

​  

 

12(6)(4)(2)

​  

 

576

​  

=24cm  

2

Step-by-step explanation:brainlist varna maut

Answer 2

Answer:

Area of triangle by heron's formulae=/S(S-A)(S-B)(S-C)

where s=semi perimeter= a+b+c/2= 6+8+10/2= 24/2= 12cm

area=/12(12-6)(12-8)(12-10)=

/12*6*4*2= /2*6*6*4*2= 2*2*6

24cm.

Area of equilateral triangle by herons formulae=

$/3a^{2}$/4=24= /3*a*a/4=24 =/3 a*a=

Step-by-step explanation: