find the side of equilateral triangle whose area is 64/3.
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s = side of equilateral ∆.
Area of equilateral∆ = √3/4 × (s)^2
64/3 = √3/4 × (s)^2
64×4/3√3 = s^2
256/3√3 = s^2
256/5.19 = s^2
49.32 = s^2
s = 7
sides of equilateral∆ = 7 unit.
....….. HOPE IT HELPS YOU.........
........ THANKS.......
==>>
s = side of equilateral ∆.
Area of equilateral∆ = √3/4 × (s)^2
64/3 = √3/4 × (s)^2
64×4/3√3 = s^2
256/3√3 = s^2
256/5.19 = s^2
49.32 = s^2
s = 7
sides of equilateral∆ = 7 unit.
....….. HOPE IT HELPS YOU.........
........ THANKS.......
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3
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