Question

FIND THE SIDE OF RECTANGLE.IF THE LENGTH IS TWO TIMES ITS BREADTH.AND AREA OF RECTANGLE IS 2048 CM SQUARE.​

Answer 1

Answer:

□length=32✔✔

□breadth=64✔✔

Step-by-step explanation:

$area \: of \: rectangle \: = {2048cm}^{2} \: \: \: (given) \\ we \: have \: to \: find \: the \: side \: of \: rectangle \\ so \: information \: given \: is \: that \: length \: of \: rectangle \: is \: twice \: to \: the \: breath \\ let \: length \: be \: = xcm \\ bredth \: be \: = 2x \\ according \: to \: question \\ area \: of \: rectangle \: = {2048cm}^{2} \\ length \times breadth = 2048 \\ x \times 2x = 2048 \\ 2 {x}^{2} = 2048\\ {x}^{2} = 1024 \\ x = \sqrt{1024} \\ x = 32 \\ length = x = 32 \\ breadth = 2x = 2 \times 32 = 64$

Answer 2

$\huge{\boxed{\sf{SOLUTION-}}}$

We clearly know the formula of area of rectangle.

Area of rectangle = Length × Breadth

Now according to question,

Let the breadth be x.

So length will be 2x.

Applying the formula,

$area \: of \: rectangle \: = length \: \times breadth$

Area of rectangle is given as 2048 cm^2

Now,

$2048 = 2x \times x \\ 2048 = {2x}^{2} \\ \frac{2048}{2} = {x}^{2}$

${x}^{2} = \frac{2048}{2} \\ {x}^{2} = 1024$

$x = \sqrt{1024}$

$x = 32$

Putting the value of x in the length which was written as 2x

Length = 2x

• = 2 × 32
• = 64

Breadth is 32

Hence,

Length of the rectangle is 64 and breadth of the rectangle is 32