Question

find the side of square whose diagonal is 16√2​

Answer 1

Step-by-step explanation:

$diagonal \: of \: square = \sqrt{2a } \\ 16 \sqrt{2 } = \sqrt{2a} \\ a = 16unit$

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Answer 2

Step-by-step explanation:

The length of diagonal of square is 16√2.

Let the side of square be X.

from Pythagoras theorem,

a×a+b×b = c×c

where, a = x , b = x c = 16√2

a2+b2= c2

x²+x²= (16√2)²

2x²= 16×16×√2×√2

2x² = 256×2

2x²= 512

x² = 512/2

x² = 256

x =√256

x = 16.

Therefore side of square is 16 units.