Question

Find the side of the square if the area of squre is 625 sq. cm

Answer 1

Answer:

25cm

Step-by-step explanation:

area of square = side²

s² = 625cm²

s = √625

s = 25cm

Therefore, side of the square is 25cm.

Answer 2

Step-by-step explanation:

Question :-

• Find the side of square whose area is 625 cm².

To Find :-

• Side of square.

Solution :-

Given :

• Area = 625 cm²

By using the formula,

${\sf{\longrightarrow Area\ of\ square\ =\ a^2}}$

Where,

• a = length of the side

According to the question, by using the formula, we get :

${\sf{\longrightarrow Area\ of\ square\ =\ a^2}}$

${\sf{\longrightarrow 625\ =\ a^2}}$

${\sf{\longrightarrow \sqrt{625}\ =\ a}}$

${\sf{\longrightarrow 25\ =\ a}}$

${\sf{\longrightarrow a\ =\ 25\ cm}}$

$\therefore$ Hence, side of square is 25 cm.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$