Question

Find the side of the square whose diagonal is 1 meter longer than its side.​

Answer 1

Let s = the length of a side of the square.

Let s + 1 = the length of the diagonal of the square.

By using Pythagoras theorem,

s² + s² = (s + 1)²

2s² = s² + 2s + 1

s² - 2s + 1 = 0

Use the quadratic formula.

s² - s - s + 1

s(s - 1) - 1(s - 1)

(s-1) (s-1)

so,

s = 1 m....

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