Find the side of the square whose diagonal is 1 meter longer than its side.
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Answered by
1
Answer:
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Answered by
0
Answer:
Let the sides and diagonal of the square is
x
and
x
+
1
meter.
respectively. Applying pythagoras formula for right triangle we
get,
x
2
+
x
2
=
(
x
+
1
)
2
or
2
x
2
=
x
2
+
2
x
+
1
or
2
x
2
−
x
2
−
2
x
−
1
=
0
or
x
2
−
2
x
=
1
or
x
2
−
2
x
+
1
=
1
+
1
or
(
x
−
1
)
2
=
2
or
(
x
−
1
)
=
±
√
2
or
x
=
1
±
√
2
∴
x
=
1
+
√
2
or
x
=
1
−
√
2
. side of a square canot be
negative .
∴
x
=
1
+
√
2
Sides of the square are
(
1
+
√
2
)
meter each.
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