Question

find the sides and perimeter of a square whose diagolnal is 10​

Answer 1

Answer:

Sides=5 root 2

perimeter of square =4 ×5 root 2

=20 root 2.

Step-by-step explanation:

hope it will help you.

Answer 2

Step-by-step explanation:

DIAGONAL=10 UNITS

AS ANGLE VERTICES OF SQUARE IS 90 DEGREE.

BY PYTHAGORAS THEOREM,

SIDE^2+SIDE^2=DIAGONAL^2      

2 x SIDE^2=10 ^2                        {AS SIDES OF SQUARES ARE EQUAL}

SIDE^2=50

SIDE= $\sqrt{50}$ UNITS.

SIDE=$\sqrt{5*5*2}$

SIDE=$5\sqrt{2}$ UNITS

PERIMETER OF SQUARE= 4 x SIDE

=4x5$\sqrt{2}$

=20$\sqrt{2}$ UNITS.