Question

Find the sides of a polygon whose interior angles are 108 degree

Answer 1

$given \\ side \: of \: the \: polygon = 108 \\ using \: the \: formula \: of \: interior \\ angle \\ 180 \times (n - 2) \div n \\ n \: is \: denoted \: as \: side \: of \: polygon \\ so \\ 108 = 180 \times (n - 2) \div n \\ (n - 2) \div n = \frac{180}{108} \\ (n - 2) \div n = \frac{5}{3} \\ (5 - 2) \div 5 \\ = 5 \\ hence \: the \: side \: is \: 5$