Question

Find the sides of a rhombus if the lengths of diagonals are 12cm and 16cm

Answer 1

Let the rhombus be ABCD Let the diagonals AC abd BD intersect at O Since diagonals of a rhombus bisect each other AO=6 BO= 8 So in triangle AOB AB^2=AO^2+BO^2 =6^2+8^2 =36+64 AB=ROOT OF 100 =10 therefore the length of the side is 10cm

Answer 2

Question:-

The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus

Solution:-

we know that diagonal of rhombus,bisect each other in right angle ( 90° ).

we also know that all sides of rhombus are equal ( of equal length ).

so, now

Let rhombus is ABCD

Let, diagonal of rhombus

BD = 16 cm and AC = 12 cm

means,

OD = 8 cm and AO = 6 cm

By pythagorus theorem

To find length of AD ( and all side of rhombus )

=> (AD)² = (OD)² + (AO)²

=> (AD)² = (8)² + (6)²

=> (AD)² = 64 + 36

=> (AD)² = 100

=> AD = √100

=> AD = 10 cm

Hence length of all side of rhombus

is 10 cm.

i hope it helps you.