Question

find the sides of a rhombus whose diagnoal are 16cm and 12cm​

Answer 1

Step-by-step explanation:

The side is

$\sqrt{ (\frac{16}{2}) {}^{2} + (\frac{12}{2}) {}^{2} } \\ = \sqrt{8 {}^{2} + 6 {}^{2} } \\ = \sqrt{64 + 36} \\ = \sqrt{100} \\ = 10 \: cm$