Question

find the sides of parallellelogram whose perimeter is 48 and the ratio of its two sides is 3:5
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Answer 1

the sides are

$\frac{48}{2} \times \frac{3}{5 + 3} \\ = 9 \\ and \\ \frac{48}{2} \times \frac{5}{5 + 3} \\ = 15$

therefore the all sides are....9,15,9,15

Answer 2

Perimeter = 48

2 sides = 3:5

3+5=8

so 3/8 * 48 = 18/2 = 9

& 5/8 * 48 = 30/2 = 15

Therefore the four sides of the parallelogram are : 9 , 15 , 9 , 15