Question

find the sides of square, whose perimeter is the same as the rectangle of length 8cm and width 2cm​

Answer 1

Answer: Side = 5 cm

Step-by-step explanation:

$\Large \bf Given:-$

Perimeter of square = Perimeter of rectangle.

Length of the rectangle = 8 cm

Width = 2 cm

$\Large \bf To\:find :-$

Sides of the square.

$\Large \bf Solution :-$

Firstly, we will find the perimeter of the rectangle of -

Length = 8 cm

Width = 2 cm

As we know,

Perimeter of the rectangle= 2(l+b)

Putting values in the formula;

Perimeter of the rectangle =2(8+2) =20cm

Now, it's given that the perimeter of the rectangle is equal to the perimeter of the square.

So, Perimeter of the square = 20 cm

But, we know perimeter of a sqaure

= 4 × side

$\implies 4 \times side = 20$

$\implies side = \frac{20}{4}$

$\implies \bf Side\:of\:the\:square= 5 cm$

Hence, each side of the square is of

5 cm.

______________________________

$\Large \bf Know\: more:-$

• Area of a rectangle = length×breadth

• Area of a square = (side)²

Answer 2

Answer:

Given-

find the sides of square, whose perimeter is the same as the rectangle of length 8cm and width 2cm.

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To find -

The find Perimeter of the rectangle and later the side of the square.

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Solution-

↬Finding the Perimeter of the rectangle is the first priority with the given length 8cm and breadth 2cm.

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

2(8+2)

2(10)

= 20cm

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↬Now, as mentioned in the above question, the Perimeter of the rectangle and the Perimeter of the antisipated square is equal.

↬So, now we will find the side of the square with Perimeter 20cm.

$\color{black}\boxed{\colorbox{saffron}{Perimeter-4×side}}$

Let the side be =x

20=4×x

=20=4x

=x=20÷4

=x=5

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Required Answer -

$\rightarrow$side of the square=5cm each